## How do you prove a group of order p 2 is abelian?

(a) A group of order p2 is abelian. If the center Z(G)=G, then G is abelian so assume that Z(G) is a proper nontrivial subgroup. Then the center must have order p and it follows that the order of the quotient G/Z(G) is p, hence G/Z(G) is a cyclic group.

### Is a group of order 2 abelian?

If the order of all nontrivial elements in a group is 2, then the group is Abelian.

#### Is p-group abelian?

Nor need a p-group be abelian; the dihedral group Dih4 of order 8 is a non-abelian 2-group. However, every group of order p2 is abelian.

**Is every group of order PQ abelian?**

(1) If p does not divide q − 1, then any group G of order pq is cyclic. (2) If p divides q − 1 then there are only two non-isomorphic groups of order pq one of which is commutative (which is again cyclic as p and q are different primes) other is non-commutative. q is Abelian. Theorem 1.3.

**Is every group of prime power order abelian?**

Is every group of the prime order abelian? Yes. The following argument is probably not the most elegant one, but it works. I claim that every group of prime order is cyclic (since every cyclic group is abelian, this shows the statement).

## Is every group of order 9 abelian?

There are, up to isomorphism, two possibilities for a group of order 9. Both of these are abelian groups and, in particular are abelian of prime power order.

### What is Abelian group with example?

Examples. Every ring is an abelian group with respect to its addition operation. In a commutative ring the invertible elements, or units, form an abelian multiplicative group. In particular, the real numbers are an abelian group under addition, and the nonzero real numbers are an abelian group under multiplication.

#### Is there a group of order 2?

There is, up to isomorphism, a unique simple group of order 2: it has two elements (1,σ), where σ⋅σ=1. on the additive group of integers. As such ℤ2 is the special case of a cyclic group ℤp for p=2 and hence also often denoted C2.

**Are P groups solvable?**

Every p p p-group is solvable.

**How do you classify abelian groups?**

Abelian groups can be classified by their order (the number of elements in the group) as the direct sum of cyclic groups. More specifically, Kronecker’s decomposition theorem. An abelian group of order n n n can be written in the form Z k 1 ⊕ Z k 2 ⊕ …

## Is a group of order 15 Abelian?

Hence by Proof by Contradiction it follows that G must be abelian. Since 15 is a product of 2 distinct primes, by Abelian Group of Semiprime Order is Cyclic, G is cyclic.

### Are all groups of order PQ cyclic?

As P and Q are cyclic groups of distinct prime order, P × Q is cyclic and so is G. Therefore, if p q − 1, then all groups of order pq are cyclic.